x+1/x^2+2x-x+4/x^2+x=-3/x^2+3x+2

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Solution for x+1/x^2+2x-x+4/x^2+x=-3/x^2+3x+2 equation: 



x+1/x^2+2x-x+4/x^2+x=-3/x^2+3x+2

We move all terms to the left:

x+1/x^2+2x-x+4/x^2+x-(-3/x^2+3x+2)=0



Domain of the equation: x^2!=0

x^2!=0/

x^2!=√0

x!=0

x∈R





Domain of the equation: x^2+3x+2)!=0

x∈R



We add all the numbers together, and all the variables

3x+1/x^2+4/x^2-(-3/x^2+3x+2)=0

We get rid of parentheses

3x+1/x^2+4/x^2+3/x^2-3x-2=0

We multiply all the terms by the denominator


3x*x^2-3x*x^2-2*x^2+1+4+3=0

We add all the numbers together, and all the variables

-2x^2+3x*x^2-3x*x^2+8=0

Wy multiply elements

-2x^2+3x^3-3x^3+8=0

We do not support expression: x^3

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